2x^2*80=-26x

Solution for 2x^2*80=-26x equation:

2x^2*80=-26x

We move all terms to the left:

2x^2*80-(-26x)=0

Wy multiply elements

160x^2-(-26x)=0

We get rid of parentheses

160x^2+26x=0

a = 160; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·160·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*160}=\frac{-52}{320}
=-13/80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*160}=\frac{0}{320}
=0
$